What is the reactive load in the same overhead circuit rated at 300 Kva with a real power load of 240 Kw?

Prepare for the 4th Year Lineman Apprentice Exam. Study with interactive resources including flashcards and multiple choice questions, each offering hints and explanations. Get exam-ready today!

To determine the reactive load in the circuit, we need to understand the relationship between real power (measured in kilowatts) and apparent power (measured in kilovolt-amperes) in an AC circuit. The formula that relates these quantities is derived from the Pythagorean theorem and is represented as:

[ S^2 = P^2 + Q^2 ]

where:

  • ( S ) is the apparent power in kVA,

  • ( P ) is the real power in kW, and

  • ( Q ) is the reactive power in kVAR.

Given that the apparent power ( S ) is 300 kVA and the real power ( P ) is 240 kW, we can rearrange the formula to solve for the reactive power ( Q ):

  1. Square the apparent power:

[ S^2 = (300)^2 = 90000 ]

  1. Square the real power:

[ P^2 = (240)^2 = 57600 ]

  1. Substitute in the formula to find ( Q^2 ):

[ Q^2 = S^2 - P^2 = 90000 -

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy